Calculator

Transformer Full-Load Current Calculator

Calculate primary and secondary full-load current of a three-phase transformer from kVA and voltages. Formula and worked examples.

Updated 2026-10-07

Protection and MVFree, no sign-upFormula and worked example
Primary full-load current52.49 A
Secondary full-load current1443.4 A
Voltage ratio27.50 : 1

Full-load current is the rated current a transformer carries at its nameplate kVA. It is the first number needed for switchgear selection, cable sizing, relay settings and fault-level estimates. Every one of those starts from the same two currents: one on the primary winding and one on the secondary.

Formula

I = kVA × 1000 / (√3 × VLL)

VLL is the line-to-line voltage of the winding in question. Apply the formula twice, once with the primary voltage and once with the secondary voltage. The kVA is the same on both sides, so the currents are inversely proportional to the voltages, apart from small losses. That inverse ratio is a quick way to check your own numbers.

Worked examples

1,000 kVA, 11 kV / 400 V. Primary: 1,000,000 / (1.732 × 11,000) = 52.5 A. Secondary: 1,000,000 / (1.732 × 400) = 1,443 A. The ratio 1,443 / 52.5 = 27.5, which equals 11,000 / 400.

500 kVA, 33 kV / 11 kV. Primary 8.75 A, secondary 26.2 A.

2,500 kVA, 11 kV / 415 V. Primary 131 A, secondary 3,478 A. A secondary current this size usually means busbar trunking and several parallel cables, not a single circuit.

What to do with the result

On the primary side, full-load current sets the minimum rating of the switchgear and the fuse or relay element. Protection is normally set well above it, because a transformer drawing magnetizing inrush on energization can take several times its rated current for a short time. Values of 8 to 12 times rated current are often quoted for inrush, and the real figure depends on the design, the residual flux in the core and the point on the voltage wave where the breaker closes. Relays on the supply side either have an inrush restraint or are set with a time delay or high enough pickup to avoid tripping on energization.

On the secondary side, the full-load current sets the size of the main breaker and the incoming cable or busbar. It is also the base for a fault-level estimate: the short-circuit current calculator divides it by the transformer impedance.

Assumptions

Common mistakes

Questions

How do I find the full-load current from the nameplate?

Many nameplates print both currents. If they do, use them. If not, calculate from kVA and the rated voltages.

Is the current the same for delta and star windings?

The line current is. The winding (phase) current differs: in a delta winding it is the line current divided by √3.

What fuse rating goes on the primary?

It depends on the standard, the fuse type and the inrush. Take the full-load current as the starting point, then follow the fuse maker’s transformer-protection tables.

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